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📐 Mathematics  ·  Trigonometric Functions  ·  JEE

Value of sin 18° =

Answer: (√5-1)/4.

  • A (√5-1)/4
  • B (√5+1)/4
  • C (√5-1)/2
  • D 1/4

Correct answer: A. (√5-1)/4

Explanation: Let θ=18°, so 5θ=90° → sin3θ=cos2θ. Expanding: 3sinθ−4sin³θ=1−2sin²θ. Set x=sinθ: 4x²+3x−1=0 (after dividing by sinθ≠0), giving x=(√5−1)/4. Answer: sin18°=(√5−1)/4.

xy0 deg30 deg45 deg (1/sqrt2, 1/sqrt2)60 deg90 degcos45sin45

Unit circle with standard angles 0, 30, 45, 60, 90 degrees; at 45 degrees the point is (cos45, sin45) = (1/sqrt2, 1/sqrt2).

Concept context

Ratios, identities, and applications in triangles

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