Zaymiey

📐 Mathematics  ·  Trigonometric Functions  ·  JEE

Value of sin 15° =

Answer: (√6-√2)/4.

  • A (√6-√2)/4
  • B (√6+√2)/4
  • C (√3-1)/2√2
  • D (√3+1)/2√2

Correct answer: A. (√6-√2)/4

Explanation: sin 15° = sin(45°-30°) = sin45°cos30° - cos45°sin30° = (√2/2)(√3/2) - (√2/2)(1/2) = (√6-√2)/4.

xy0 deg30 deg45 deg (1/sqrt2, 1/sqrt2)60 deg90 degcos45sin45

Unit circle with standard angles 0, 30, 45, 60, 90 degrees; at 45 degrees the point is (cos45, sin45) = (1/sqrt2, 1/sqrt2).

Concept context

Ratios, identities, and applications in triangles

Read the full Trigonometric Functions notes →