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📐 Mathematics  ·  Trigonometric Functions  ·  JEE

The range of f(x) = 3sinx + 4cosx + 5 is:

Answer: [0, 10].

  • A [−5, 5]
  • B [0, 10]
  • C [1, 9]
  • D [2, 8]

Correct answer: B. [0, 10]

Explanation: 3sinx + 4cosx lies in [−5, 5] since the amplitude is √(9+16) = 5. Adding 5 gives [0, 10].

xy0 deg30 deg45 deg (1/sqrt2, 1/sqrt2)60 deg90 degcos45sin45

Unit circle with standard angles 0, 30, 45, 60, 90 degrees; at 45 degrees the point is (cos45, sin45) = (1/sqrt2, 1/sqrt2).

Concept context

Ratios, identities, and applications in triangles

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