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📐 Mathematics  ·  Trigonometric Functions  ·  JEE

Find the general solution of sin θ = 1/2.

Answer: θ = nπ + (-1)ⁿ π/6.

  • A θ = 30°
  • B θ = nπ + (-1)ⁿ π/6
  • C θ = 30° + 360°n
  • D θ = π/6 only

Correct answer: B. θ = nπ + (-1)ⁿ π/6

Explanation: General solution: θ = nπ + (-1)ⁿ α, where sin α = 1/2, α = π/6.

xy0 deg30 deg45 deg (1/sqrt2, 1/sqrt2)60 deg90 degcos45sin45

Unit circle with standard angles 0, 30, 45, 60, 90 degrees; at 45 degrees the point is (cos45, sin45) = (1/sqrt2, 1/sqrt2).

Concept context

Ratios, identities, and applications in triangles

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