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📐 Mathematics  ·  Trigonometric Functions  ·  JEE

Express sin 3A in terms of sin A.

Answer: 3sinA - 4sin³A.

  • A 3sinA - 4sin³A
  • B 4sinA - 3sin³A
  • C 3sinA + 4sin³A
  • D sin³A + 3sinA

Correct answer: A. 3sinA - 4sin³A

Explanation: sin 3A = 3 sinA - 4 sin³A. (Standard triple angle formula).

xy0 deg30 deg45 deg (1/sqrt2, 1/sqrt2)60 deg90 degcos45sin45

Unit circle with standard angles 0, 30, 45, 60, 90 degrees; at 45 degrees the point is (cos45, sin45) = (1/sqrt2, 1/sqrt2).

Concept context

Ratios, identities, and applications in triangles

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