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📐 Mathematics  ·  Straight Lines  ·  JEE

The locus of points equidistant from (3,0) and (-3,0) is:

Answer: x = 0.

  • A x = 0
  • B y = 0
  • C x² + y² = 9
  • D y = x

Correct answer: A. x = 0

Explanation: Points equidistant from (3,0) and (-3,0) lie on the perpendicular bisector of segment joining them: x = 0.

Slope as Rise over Runxy(x₁,y₁)(x₂,y₂)run = x₂−x₁rise = y₂−y₁m = rise/run = (y₂−y₁)/(x₂−x₁) = tanθ

The slope of a line is the ratio of vertical change (rise) to horizontal change (run) between any two points on it - equivalently, the tangent of the angle θ the line makes with the positive x-axis.

Concept context

Points, lines, and curves on the Cartesian plane

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