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📐 Mathematics  ·  Statistics  ·  JEE

The variance of combined data of two groups (n₁, x̄₁, σ₁²) and (n₂, x̄₂, σ₂²) is:

Answer: A more complex formula involving d₁² and d₂² (distances from combined mean).

  • A (n₁σ₁²+n₂σ₂²)/(n₁+n₂), which overlooks the shift in means between the two groups
  • B A more complex formula involving d₁² and d₂² (distances from combined mean)
  • C (σ₁²+σ₂²)/2, a simple unweighted average that ignores group sizes
  • D σ₁ × σ₂, the simple product of the two individual standard deviations

Correct answer: B. A more complex formula involving d₁² and d₂² (distances from combined mean)

Explanation: Combined mean x̄ = (n₁x̄₁+n₂x̄₂)/(n₁+n₂). Let d₁ = x̄₁−x̄ and d₂ = x̄₂−x̄. Combined variance = [n₁(σ₁²+d₁²) + n₂(σ₂²+d₂²)]/(n₁+n₂). The d² terms capture the shift between group means and the combined mean.

Normal Distribution: the 68-95-99.7 Rule68% within ±1σ95% within ±2σmean=median=mode (centre)

In a perfectly normal (bell-shaped) distribution, mean, median, and mode all coincide at the centre; about 68% of data falls within 1 standard deviation of the mean, 95% within 2, and 99.7% within 3 - the empirical rule used to judge how typical or extreme a value is.

Concept context

Mean, median, mode, standard deviation, and data interpretation

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