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📐 Mathematics  ·  Relations and Functions  ·  JEE

The domain of f(x) = sqrt(4 - x²) is:

Answer: [-2, 2].

  • A [-2, 2]
  • B (-2, 2)
  • C [0, 2]
  • D All reals

Correct answer: A. [-2, 2]

Explanation: We need 4 - x² is greater than or equal to 0, i.e., x² is less than or equal to 4, so -2 is less than or equal to x is less than or equal to 2.

Concept context

Ordered pairs, Cartesian products, types of relations and functions, domain and range. Foundation for calculus and Class 12 algebra.

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