Answer: Neither injective nor surjective.
- A Injective but not surjective
- B Surjective but not injective
- C Both injective and surjective
- D Neither injective nor surjective
Correct answer: D. Neither injective nor surjective
Explanation: f(2) = f(-2) = 2, so not injective. Also range = [0, inf), not all of R, so not surjective.
Concept context
Ordered pairs, Cartesian products, types of relations and functions, domain and range. Foundation for calculus and Class 12 algebra.