Answer: Bijective.
- A Injective but not surjective
- B Surjective but not injective
- C Bijective
- D Neither
Correct answer: C. Bijective
Explanation: Injective: f(a)=f(b) ⟹ a³=b³ ⟹ a=b (cube root is unique in R). Surjective: for any y∈R, x=y<sup>1/3</sup> ∈ R satisfies f(x)=y (every real has a real cube root). Both injective and surjective ⟹ bijective. Answer: f(x)=x³ is bijective
Concept context
Ordered pairs, Cartesian products, types of relations and functions, domain and range. Foundation for calculus and Class 12 algebra.