Answer: 1.
- A 0
- B μ
- C 1
- D n
Correct answer: C. 1
Explanation: Kolmogorov axioms: for any event A, P(A) ≥ 0; P(S) = 1. For a discrete RV, {X=x} are mutually exclusive events partitioning S, so Σₓ P(X=x) = P(S) = 1. This is the normalisation condition for any valid PMF.
Venn diagram of the universal set U with events A and B, showing the intersection (A and B), the parts unique to each event, and the complement region outside both.
Concept context
Chance, events, conditional probability, and Bayes theorem