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📐 Mathematics  ·  Principle of Mathematical Induction  ·  JEE

While proving 2<sup>2n</sup> - 1 is divisible by 3 by induction, the inductive step rewrites 2^(2(k+1)) - 1 as:

Answer: 4(2 2k - 1) + 3.

  • A (2<sup>2k</sup> - 1) + 4
  • B 4(2<sup>2k</sup> - 1) + 3
  • C 4(2<sup>2k</sup> - 1) - 3
  • D 2(2<sup>2k</sup> - 1) + 1

Correct answer: B. 4(2<sup>2k</sup> - 1) + 3

Explanation: 2<sup>2k+2</sup> - 1 = 4 . 2<sup>2k</sup> - 1 = 4(2<sup>2k</sup> - 1) + 3, and since 2<sup>2k</sup> - 1 is divisible by 3 by the inductive hypothesis, the whole expression is divisible by 3.

Induction as a Domino ChainP(1): base case fallsP(k) knocks down P(k+1)...and so on, foreverBase case = first domino tipped; inductive step = each domino guaranteed to tip the next one

Mathematical induction works like a row of dominoes: proving the base case P(1) tips the first domino, and proving the inductive step (P(k) ⟹ P(k+1)) guarantees each domino knocks over the next - together these two facts guarantee ALL dominoes fall, without checking each one individually.

Concept context

A proof technique used to establish that a statement is true for every natural number, using a base case and an inductive step.

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