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📐 Mathematics  ·  Principle of Mathematical Induction  ·  JEE

To prove that 7<sup>n</sup> - 3<sup>n</sup> is divisible by 4 for all natural numbers n, the inductive step writes 7<sup>k+1</sup> - 3<sup>k+1</sup> as:

Answer: 7(7 k - 3 k ) + 4(3 k ).

  • A 7(7<sup>k</sup> - 3<sup>k</sup>) + 4(3<sup>k</sup>)
  • B 7<sup>k</sup> - 3<sup>k</sup> + 4
  • C 7 x 7<sup>k</sup> - 3 x 3<sup>k</sup> only, with no simplification
  • D 4(7<sup>k</sup> - 3<sup>k</sup>)

Correct answer: A. 7(7<sup>k</sup> - 3<sup>k</sup>) + 4(3<sup>k</sup>)

Explanation: 7<sup>k+1</sup> - 3<sup>k+1</sup> = 7 x 7<sup>k</sup> - 3 x 3<sup>k</sup> = 7(7<sup>k</sup> - 3<sup>k</sup>) + 7(3<sup>k</sup>) - 3(3<sup>k</sup>) = 7(7<sup>k</sup>-3<sup>k</sup>) + 4(3<sup>k</sup>). Since 7<sup>k</sup>-3<sup>k</sup> is divisible by 4 (hypothesis) and 4(3<sup>k</sup>) is clearly divisible by 4, the whole expression is divisible by 4.

Induction as a Domino ChainP(1): base case fallsP(k) knocks down P(k+1)...and so on, foreverBase case = first domino tipped; inductive step = each domino guaranteed to tip the next one

Mathematical induction works like a row of dominoes: proving the base case P(1) tips the first domino, and proving the inductive step (P(k) ⟹ P(k+1)) guarantees each domino knocks over the next - together these two facts guarantee ALL dominoes fall, without checking each one individually.

Concept context

A proof technique used to establish that a statement is true for every natural number, using a base case and an inductive step.

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