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📐 Mathematics  ·  Principle of Mathematical Induction  ·  JEE

To prove n! > 2<sup>n</sup> for all natural numbers n >= 4 by induction, what should the base case be?

Answer: n = 4.

  • A n = 1
  • B n = 4
  • C n = 0
  • D n = 2

Correct answer: B. n = 4

Explanation: The inequality n! > 2<sup>n</sup> is false for n=1,2,3 (check: 1!=1 vs 2, 2!=2 vs 4, 3!=6 vs 8, all fail), but holds from n=4 onward (4!=24 > 16=2<sup>4</sup>). So the base case must be n=4.

Induction as a Domino ChainP(1): base case fallsP(k) knocks down P(k+1)...and so on, foreverBase case = first domino tipped; inductive step = each domino guaranteed to tip the next one

Mathematical induction works like a row of dominoes: proving the base case P(1) tips the first domino, and proving the inductive step (P(k) ⟹ P(k+1)) guarantees each domino knocks over the next - together these two facts guarantee ALL dominoes fall, without checking each one individually.

Concept context

A proof technique used to establish that a statement is true for every natural number, using a base case and an inductive step.

Read the full Principle of Mathematical Induction notes →