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📐 Mathematics  ·  Principle of Mathematical Induction  ·  JEE

In the inductive step for the sum of first n odd numbers, what is added to k<sup>2</sup> to get the next term?

Answer: 2k + 1.

  • A 2k - 1
  • B 2k + 1
  • C k + 1
  • D 2k

Correct answer: B. 2k + 1

Explanation: The (k+1)th odd number is 2(k+1) - 1 = 2k + 1. Adding this to k<sup>2</sup> gives k<sup>2</sup> + 2k + 1 = (k+1)<sup>2</sup>, proving P(k+1).

Induction as a Domino ChainP(1): base case fallsP(k) knocks down P(k+1)...and so on, foreverBase case = first domino tipped; inductive step = each domino guaranteed to tip the next one

Mathematical induction works like a row of dominoes: proving the base case P(1) tips the first domino, and proving the inductive step (P(k) ⟹ P(k+1)) guarantees each domino knocks over the next - together these two facts guarantee ALL dominoes fall, without checking each one individually.

Concept context

A proof technique used to establish that a statement is true for every natural number, using a base case and an inductive step.

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