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📐 Mathematics  ·  Principle of Mathematical Induction  ·  JEE

For proving n<sup>2</sup> < 2<sup>n</sup> for all natural numbers n >= 5, what must be verified before applying the inductive step?

Answer: That the base case n=5 holds: 25 < 32.

  • A That the base case n=5 holds: 25 < 32
  • B That n=1 holds: 1 < 2
  • C Nothing, induction applies automatically
  • D That n=4 holds: 16 < 16

Correct answer: A. That the base case n=5 holds: 25 < 32

Explanation: The inequality n<sup>2</sup> < 2<sup>n</sup> fails for n=1,2,3,4 (at n=4: 16 < 16 is false since they are equal), but holds from n=5 onward (25 < 32). The base case must therefore be verified at n=5.

Induction as a Domino ChainP(1): base case fallsP(k) knocks down P(k+1)...and so on, foreverBase case = first domino tipped; inductive step = each domino guaranteed to tip the next one

Mathematical induction works like a row of dominoes: proving the base case P(1) tips the first domino, and proving the inductive step (P(k) ⟹ P(k+1)) guarantees each domino knocks over the next - together these two facts guarantee ALL dominoes fall, without checking each one individually.

Concept context

A proof technique used to establish that a statement is true for every natural number, using a base case and an inductive step.

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