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📐 Mathematics  ·  Permutations and Combinations  ·  JEE

Total number of permutations of n items with repetitions: n₁ alike, n₂ alike,..., nk alike (sum = n) =

Answer: n!/(n₁! n₂! ... nk!).

  • A n!
  • B n!/(n₁! n₂! ... nk!)
  • C n!/(n₁+n₂+...)
  • D n × n!

Correct answer: B. n!/(n₁! n₂! ... nk!)

Explanation: Multinomial coefficient: start with n! total arrangements, divide by n₁! for identical group 1, n₂! for group 2, etc. Result: n!/(n₁!n₂!…nk!).

StartABCBCACAB6 ordered outcomes (permutations); pairing AB/BA etc gives 3 combinations

Counting tree for selecting 2 items from {A, B, C} without repetition: 3 x 2 = 6 ordered arrangements.

Concept context

Counting, arrangements, and selections

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