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📐 Mathematics  ·  Permutations and Combinations  ·  JEE

Number of ways to select 3 from 6 where order matters for first 2 but not the third:

Answer: 6P2 × 4C1.

  • A 6P2 × 4
  • B 6C3 × 2
  • C 6P2 × 4C1
  • D 6 × 5 × 4

Correct answer: C. 6P2 × 4C1

Explanation: Step 1: arrange first 2 from 6 in order → 6P2 = 6×5 = 30. Step 2: pick the 3rd from remaining 4 (unordered) → 4C1 = 4. Total = 30×4 = 120 = 6P2×4C1.

StartABCBCACAB6 ordered outcomes (permutations); pairing AB/BA etc gives 3 combinations

Counting tree for selecting 2 items from {A, B, C} without repetition: 3 x 2 = 6 ordered arrangements.

Concept context

Counting, arrangements, and selections

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