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📐 Mathematics  ·  Permutations and Combinations  ·  JEE

nPr = r! × nCr. True or false?

Answer: True.

  • A True
  • B False, claiming the identity does not actually hold
  • C Valid just for the special case r=2
  • D Valid just for the special case n=r

Correct answer: A. True

Explanation: nPr = n!/(n-r)! and nCr = n!/[r!(n-r)!]. So nPr = r! × nCr. True.

StartABCBCACAB6 ordered outcomes (permutations); pairing AB/BA etc gives 3 combinations

Counting tree for selecting 2 items from {A, B, C} without repetition: 3 x 2 = 6 ordered arrangements.

Concept context

Counting, arrangements, and selections

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