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📐 Mathematics  ·  Limits and Derivatives  ·  JEE

The Mean Value Theorem states that for f on [a,b]:

Answer: f(b)-f(a) = f'(c)(b-a) for some c in (a,b).

  • A f(c) = 0 for some c
  • B f(b)-f(a) = f(c)(b-a) for some c in (a,b)
  • C f(b)-f(a) = f'(c)(b-a) for some c in (a,b)
  • D f is monotone

Correct answer: C. f(b)-f(a) = f'(c)(b-a) for some c in (a,b)

Explanation: MVT (Lagrange): if f is continuous on [a,b] and differentiable on (a,b), there exists c in (a,b) such that f'(c) = [f(b)-f(a)]/(b-a).

xyP (a, f(a))Q (b, f(b))secant PQtangent at PAs Q slides toward P, secant approaches tangent

As point Q slides along the curve toward P, the secant line PQ rotates into the tangent line at P, whose slope is the derivative.

Concept context

Rate of change, differentiation rules, and applications

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