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📐 Mathematics  ·  Inverse Trigonometric Functions  ·  JEE

The range of cot-1 x excludes which value?

Answer: It excludes both 0 and pi as open endpoints.

  • A 0, since the range starts strictly above zero
  • B pi/2, a value that cot-1 x does not actually reach
  • C pi, a value that cot-1 x does not actually attain
  • D It excludes both 0 and pi as open endpoints

Correct answer: D. It excludes both 0 and pi as open endpoints

Explanation: The principal value range of cot-1 x is the open interval (0, pi), so both endpoints 0 and pi are excluded.

y = sin⁻¹x: Principal Value Branchxyx=-1x=1y=-π/2y=π/2Domain restricted to [-1,1]; range restricted to [-π/2,π/2] - this restriction is what makes the inverse exist

The graph of sin⁻¹x is confined to a narrow domain [-1,1] (since sine itself only takes values in that range) and range [-π/2,π/2] (the principal value branch chosen to make sine one-one and invertible there).

Concept context

Restricting trig functions to make them invertible, the principal value branches of sin-inverse, cos-inverse, tan-inverse, and friends, and the key identities relating them.

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