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📐 Mathematics  ·  Inverse Trigonometric Functions  ·  JEE

Solve for x: 2 tan-1(cos x) = tan-1(2 cosec x), for x in (0, pi/2).

Answer: x = pi/4.

  • A x = pi/4
  • B x = pi/6
  • C x = pi/3
  • D x = pi/2

Correct answer: A. x = pi/4

Explanation: At x = pi/4: cos(pi/4) = 1/sqrt2, cosec(pi/4) = sqrt2. LHS: 2tan-1(1/sqrt2). RHS: tan-1(2sqrt2). Using the double angle formula 2tan-1(1/sqrt2) = tan-1[2(1/sqrt2)/(1-1/2)] = tan-1[sqrt2/(1/2)] = tan-1(2sqrt2), matching RHS, confirming x=pi/4 works.

y = sin⁻¹x: Principal Value Branchxyx=-1x=1y=-π/2y=π/2Domain restricted to [-1,1]; range restricted to [-π/2,π/2] - this restriction is what makes the inverse exist

The graph of sin⁻¹x is confined to a narrow domain [-1,1] (since sine itself only takes values in that range) and range [-π/2,π/2] (the principal value branch chosen to make sine one-one and invertible there).

Concept context

Restricting trig functions to make them invertible, the principal value branches of sin-inverse, cos-inverse, tan-inverse, and friends, and the key identities relating them.

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