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Second Mean Value Theorem for integrals: integral from a to b of f(x)g(x) dx =

Answer: f(c) × integral from a to b of g(x) dx for some c in [a,b].

  • A f(c) × integral from a to b of g(x) dx for some c in [a,b]
  • B f(a) × G(b) + f(b) × [G(b)-G(a)], an integration-by-parts-style expansion
  • C The product of integral f(x) dx and integral g(x) dx taken separately
  • D Cannot be simplified beyond the original product integral

Correct answer: A. f(c) × integral from a to b of g(x) dx for some c in [a,b]

Explanation: Second MVT for integrals: if f is monotone and g is integrable, then integral fg = f(c) integral g for some c. Generalization allows Bonnet form.

xyabArea = integral of f(x) dxRectangles approximate the area (Riemann sum)

The exact area under the curve from a to b (shaded) is approximated by a few rectangles, the Riemann sum idea behind the definite integral.

Concept context

Indefinite and definite integrals, areas under curves

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