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📐 Mathematics  ·  Integrals  ·  JEE

Evaluate: integral of (sin 2x)/(1+sin²x) dx.

Answer: ln(1+sin²x) + C.

  • A ln(1+sin²x) + C
  • B 2 sin²x + C
  • C tan⁻¹(sinx) + C
  • D -cos 2x + C

Correct answer: A. ln(1+sin²x) + C

Explanation: Note sin2x = 2sinx cosx = d(sin²x)/dx. Substitution u=1+sin²x, du=sin2x dx. Integral = ∫du/u = ln|u|+C = ln(1+sin²x)+C. Since 1+sin²x≥1>0, absolute value is unnecessary.

xyabArea = integral of f(x) dxRectangles approximate the area (Riemann sum)

The exact area under the curve from a to b (shaded) is approximated by a few rectangles, the Riemann sum idea behind the definite integral.

Concept context

Indefinite and definite integrals, areas under curves

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