Answer: P = P₀ e kt.
- A P = P₀ + kt
- B P = P₀ e<sup>kt</sup>
- C P = kt
- D P = P₀/k
Correct answer: B. P = P₀ e<sup>kt</sup>
Explanation: Separate: dP/P = k dt. Integrate: ln P = kt + C. P = P₀ e<sup>kt</sup>. Classic exponential growth.
The general solution y=Ax² represents an entire FAMILY of curves, one for each value of the arbitrary constant A; a particular solution (fixed by an initial condition) selects exactly one curve from this family.
Concept context
Equations involving derivatives and their solutions