📐 Mathematics · Determinants · JEE

If ω is a non-real cube root of unity, the determinant of [[1, ω, ω²], [ω, ω², 1], [ω², 1, ω]] is:

Answer: 0.

Correct answer: A. 0

Explanation: Because 1 + ω + ω² = 0, the rows are linearly dependent and the determinant is 0.

Concept context

Evaluation of determinants, cofactors, adjoint, inverse of matrix, Cramer's rule and area applications. Always in board and JEE.