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📐 Mathematics  ·  Conic Sections  ·  JEE

The latus rectum of an ellipse is half of its minor axis. Find the eccentricity of the ellipse.

Answer: sqrt(3)/2.

  • A 1/2
  • B sqrt(3)/2
  • C 1/sqrt(2)
  • D sqrt(2)/3

Correct answer: B. sqrt(3)/2

Explanation: Latus rectum = 2b<sup>2</sup>/a. Minor axis = 2b. Given 2b<sup>2</sup>/a = (1/2)(2b) = b, so 2b<sup>2</sup>/a = b gives 2b = a, b = a/2. Then e<sup>2</sup> = 1 - b<sup>2</sup>/a<sup>2</sup> = 1 - 1/4 = 3/4, so e = sqrt(3)/2.

The Four Conics by EccentricityCircle (e=0)Ellipse (0<e<1)Parabola (e=1)Hyperbola (e>1)

All four conics form a single family distinguished only by eccentricity: a circle is the most "closed" (e=0), an ellipse is an elongated closed curve, a parabola is the borderline open curve (e=1), and a hyperbola has two separate open branches (e>1).

Concept context

Study circles, parabolas, ellipses, and hyperbolas as curves formed by intersecting a plane with a double cone, with their standard equations and key properties.

Read the full Conic Sections notes →