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📐 Mathematics  ·  Conic Sections  ·  JEE

Identify the conic represented by 9x<sup>2</sup> + 25y<sup>2</sup> = 225 and find its eccentricity.

Answer: Ellipse, e = 4/5.

  • A Ellipse, e = 4/5
  • B Ellipse, e = 3/5
  • C Hyperbola, e = 4/5
  • D Circle, e = 0

Correct answer: A. Ellipse, e = 4/5

Explanation: Dividing by 225: x<sup>2</sup>/25 + y<sup>2</sup>/9 = 1, an ellipse with a<sup>2</sup>=25, b<sup>2</sup>=9. c<sup>2</sup>=16, c=4, e=c/a=4/5.

The Four Conics by EccentricityCircle (e=0)Ellipse (0<e<1)Parabola (e=1)Hyperbola (e>1)

All four conics form a single family distinguished only by eccentricity: a circle is the most "closed" (e=0), an ellipse is an elongated closed curve, a parabola is the borderline open curve (e=1), and a hyperbola has two separate open branches (e>1).

Concept context

Study circles, parabolas, ellipses, and hyperbolas as curves formed by intersecting a plane with a double cone, with their standard equations and key properties.

Read the full Conic Sections notes →