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📐 Mathematics  ·  Conic Sections  ·  JEE

For an ellipse x<sup>2</sup>/a<sup>2</sup> + y<sup>2</sup>/b<sup>2</sup> = 1 with a > b, the relationship between a, b, and c (distance to focus) is:

Answer: c 2 = a 2 - b 2.

  • A c<sup>2</sup> = a<sup>2</sup> + b<sup>2</sup>
  • B c<sup>2</sup> = a<sup>2</sup> - b<sup>2</sup>
  • C c<sup>2</sup> = b<sup>2</sup> - a<sup>2</sup>
  • D c = a + b

Correct answer: B. c<sup>2</sup> = a<sup>2</sup> - b<sup>2</sup>

Explanation: For an ellipse, c<sup>2</sup> = a<sup>2</sup> - b<sup>2</sup>, since the foci lie inside the ellipse.

The Four Conics by EccentricityCircle (e=0)Ellipse (0<e<1)Parabola (e=1)Hyperbola (e>1)

All four conics form a single family distinguished only by eccentricity: a circle is the most "closed" (e=0), an ellipse is an elongated closed curve, a parabola is the borderline open curve (e=1), and a hyperbola has two separate open branches (e>1).

Concept context

Study circles, parabolas, ellipses, and hyperbolas as curves formed by intersecting a plane with a double cone, with their standard equations and key properties.

Read the full Conic Sections notes →