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📐 Mathematics  ·  Conic Sections  ·  JEE

Find the equation of the parabola with vertex at the origin, axis along the x-axis, and passing through the point (2, 4).

Answer: y 2 = 8x.

  • A y<sup>2</sup> = 8x
  • B y<sup>2</sup> = 4x
  • C y<sup>2</sup> = 16x
  • D y<sup>2</sup> = 2x

Correct answer: A. y<sup>2</sup> = 8x

Explanation: Standard form y²=4ax. Substituting point (2,4): 4²=4a(2) → 16=8a → a=2. So 4a=8. Equation: y²=8x. Verify: (2,4)→16=8(2)=16. ✓ Ans: y²=8x.

The Four Conics by EccentricityCircle (e=0)Ellipse (0<e<1)Parabola (e=1)Hyperbola (e>1)

All four conics form a single family distinguished only by eccentricity: a circle is the most "closed" (e=0), an ellipse is an elongated closed curve, a parabola is the borderline open curve (e=1), and a hyperbola has two separate open branches (e>1).

Concept context

Study circles, parabolas, ellipses, and hyperbolas as curves formed by intersecting a plane with a double cone, with their standard equations and key properties.

Read the full Conic Sections notes →