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📐 Mathematics  ·  Conic Sections  ·  JEE

An ellipse has vertices (±5, 0) and foci (±3, 0). Find its equation.

Answer: x 2 /25 + y 2 /16 = 1.

  • A x<sup>2</sup>/25 + y<sup>2</sup>/9 = 1
  • B x<sup>2</sup>/25 + y<sup>2</sup>/16 = 1
  • C x<sup>2</sup>/16 + y<sup>2</sup>/25 = 1
  • D x<sup>2</sup>/9 + y<sup>2</sup>/25 = 1

Correct answer: B. x<sup>2</sup>/25 + y<sup>2</sup>/16 = 1

Explanation: a=5, c=3, so b<sup>2</sup> = a<sup>2</sup>-c<sup>2</sup> = 25-9 = 16. Equation: x<sup>2</sup>/25 + y<sup>2</sup>/16 = 1.

The Four Conics by EccentricityCircle (e=0)Ellipse (0<e<1)Parabola (e=1)Hyperbola (e>1)

All four conics form a single family distinguished only by eccentricity: a circle is the most "closed" (e=0), an ellipse is an elongated closed curve, a parabola is the borderline open curve (e=1), and a hyperbola has two separate open branches (e>1).

Concept context

Study circles, parabolas, ellipses, and hyperbolas as curves formed by intersecting a plane with a double cone, with their standard equations and key properties.

Read the full Conic Sections notes →