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📐 Mathematics  ·  Conic Sections  ·  JEE

An ellipse and a hyperbola have the same foci. If the ellipse has eccentricity 3/5 and the hyperbola has eccentricity 5/3, and the ellipse's semi-major axis is 10, find c (distance from center to focus).

Answer: 6.

  • A 5
  • B 6
  • C 8
  • D 10

Correct answer: B. 6

Explanation: For the ellipse: e=c/a=3/5, a=10. So c=(3/5)×10=6. Both conics share the same foci, so the common focal distance is c=6. Verify: hyperbola e=c/a<sub>h</sub>=5/3 → a<sub>h</sub>=c×3/5=18/5. Ans: c=6.

The Four Conics by EccentricityCircle (e=0)Ellipse (0<e<1)Parabola (e=1)Hyperbola (e>1)

All four conics form a single family distinguished only by eccentricity: a circle is the most "closed" (e=0), an ellipse is an elongated closed curve, a parabola is the borderline open curve (e=1), and a hyperbola has two separate open branches (e>1).

Concept context

Study circles, parabolas, ellipses, and hyperbolas as curves formed by intersecting a plane with a double cone, with their standard equations and key properties.

Read the full Conic Sections notes →