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📐 Mathematics  ·  Binomial Theorem  ·  JEE

The sum nC<sub>0</sub> + nC<sub>2</sub> + nC<sub>4</sub> + ... (even-indexed coefficients) =

Answer: 2ⁿ⁻¹.

  • A 2ⁿ
  • B n
  • C 2ⁿ⁻¹
  • D 2ⁿ⁻²

Correct answer: C. 2ⁿ⁻¹

Explanation: Sum of even-indexed binomial coefficients = 2<sup>n-1</sup>. This follows from adding (1+1)<sup>n</sup> and (1-1)<sup>n</sup> then halving.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →