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📐 Mathematics  ·  Binomial Theorem  ·  JEE

The sum nC0 − nC1 + nC2 − ... = ?

Answer: 0.

  • A 2ⁿ
  • B 2ⁿ⁻¹
  • C 1
  • D 0

Correct answer: D. 0

Explanation: Put x = -1 in (1+x)n: (1-1)n = 0 = nC0 - nC1 + nC2 - .... So the alternating sum = 0.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →