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The sum nC<sub>0</sub> − nC<sub>1</sub> + nC<sub>2</sub> − ... = ?

Answer: 0.

  • A 2ⁿ
  • B 2ⁿ⁻¹
  • C 1
  • D 0

Correct answer: D. 0

Explanation: Put x = -1 in (1+x)<sup>n</sup>: (1-1)<sup>n</sup> = 0 = nC<sub>0</sub> - nC<sub>1</sub> + nC<sub>2</sub> - .... So the alternating sum = 0.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →