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📐 Mathematics  ·  Binomial Theorem  ·  JEE

The second term T₂ in the expansion of (a+b)ⁿ is:

Answer: nC 1 a n-1 b.

  • A nCn-1 a b<sup>n-1</sup>
  • B n a<sup>n-1</sup> b²
  • C nC<sub>2</sub> a<sup>n-2</sup> b²
  • D nC<sub>1</sub> a<sup>n-1</sup> b

Correct answer: D. nC<sub>1</sub> a<sup>n-1</sup> b

Explanation: T<sub>2</sub> = T(1+1) = nC<sub>1</sub> a<sup>n-1</sup> b<sup>1</sup> = n a<sup>n-1</sup> b.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

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