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📐 Mathematics  ·  Binomial Theorem  ·  JEE

The number of terms in (a + b + c)ⁿ is:

Answer: (n+1)(n+2)/2.

  • A n+1, the count for a two-variable expansion
  • B n+2, one more than the two-variable case
  • C (n+1)(n+2)/2
  • D 3n, treating each variable as contributing separately

Correct answer: C. (n+1)(n+2)/2

Explanation: Number of terms in expansion of (a+b+c)<sup>n</sup> = (n+1)(n+2)/2 (using stars and bars).

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →