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The largest term in the expansion of (3 + 5x)¹⁰ when x = 1/5 is:

Answer: T₃.

  • A T₄
  • B T₅
  • C T₃
  • D T₆

Correct answer: C. T₃

Explanation: With x=1/5, 5x=1, so T(r+1)=C(10,r)*3<sup>10-r</sup>. Computing directly: T<sub>1</sub>=3<sup>10</sup>=59049, T<sub>2</sub>=10*3<sup>9</sup>=196830, T3=45*3<sup>8</sup>=295245, T<sub>4</sub>=120*3<sup>7</sup>=262440. Since T3 exceeds both T<sub>2</sub> and T<sub>4</sub>, T3 is the largest term.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

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