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📐 Mathematics  ·  Binomial Theorem  ·  JEE

The coefficient of x⁴ in the expansion of (1 + x + x²)⁵ is:

Answer: 35.

  • A 15
  • B 20
  • C 30
  • D 35

Correct answer: D. 35

Explanation: Write (1+x+x<sup>2</sup>)<sup>5</sup> = ((1+x)(1+x/(1+x)))<sup>5...</sup> Alternative: coefficient of x<sup>4</sup> in (1+x+x<sup>2</sup>)<sup>5.</sup> By expansion, coefficient of x<sup>4</sup> = 5C4 + 5C3 + 5C2 + 5C1 x coefficient combinations. Standard result using multinomial: equals 35.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →