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📐 Mathematics  ·  Binomial Theorem  ·  JEE

The coefficient of x⁵ in (1 + x²)⁵(1 + x)⁴ is:

Answer: 60.

  • A 60
  • B 61
  • C 62
  • D 63

Correct answer: A. 60

Explanation: Coeff of x5 in (1+x2)5(1+x)4: from (1+x2)5, only even powers x0, x2, x4 are available (max x10), and from (1+x)4 only powers up to x4 are available. Pairing to total x5: x2 from the first with x3 from the second gives C(5,1)*C(4,3) = 5*4=20; x4 from the first with x1 from the second gives C(5,2)*C(4,1) = 10*4=40. Total = 20+40 = 60.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →