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📐 Mathematics  ·  Binomial Theorem  ·  JEE

In (1+x)ⁿ, if the coefficient of x² equals the coefficient of x³, find n.

Answer: 5.

  • A 4
  • B 3
  • C 5
  • D 6

Correct answer: C. 5

Explanation: nC<sub>2</sub> = nC<sub>3</sub>: n!/(2!(n-2)!) = n!/(3!(n-3)!). Simplify: 1/2 = 1/(3(n-3)+3) ... nC<sub>2</sub> = nC<sub>3</sub> means (n-2)/2! = 1/3! wait: nC<sub>2</sub> = n(n-1)/2 and nC<sub>3</sub> = n(n-1)(n-2)/6. Set equal: 3 = n-2, n = 5.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →