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📐 Mathematics  ·  Binomial Theorem  ·  JEE

If the coefficients of x⁷ and x⁸ in (2 + x/3)ⁿ are equal, find n.

Answer: 55.

  • A 45
  • B 46
  • C 56
  • D 55

Correct answer: D. 55

Explanation: T<sub>8</sub> = nC7 (2)<sup>n-7</sup> (x/3)<sup>7</sup> and T9 = nC8 (2)<sup>n-8</sup> (x/3)<sup>8.</sup> Equal coefficients: nC7/nC8 = 2/3. Since nC8/nC7 = (n-7)/8, we get (n-7)/8 = 3/2. n-7 = 12. n = 55.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →