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📐 Mathematics  ·  Binomial Theorem  ·  JEE

If (1 + ax)ⁿ = 1 + 6x + 12x² + ..., find a and n.

Answer: a=2, n=3.

  • A a=2, n=3
  • B a=1, n=6
  • C a=3, n=2
  • D a=2, n=4

Correct answer: A. a=2, n=3

Explanation: Coefficient of x: na = 6. Coefficient of x²: n(n-1)a²/2 = 12. From na=6, a=6/n. Substituting: n(n-1)(36/n²)/2=12, so 18(n-1)/n=12, giving 18n-18=12n, 6n=18, n=3, a=2.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

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