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📐 Mathematics  ·  Binomial Theorem  ·  JEE

Find the term independent of x in (x² + 1/x³)¹⁰.

Answer: 10C4.

  • A 10C4
  • B 10C2 = 45
  • C 120
  • D 252

Correct answer: A. 10C4

Explanation: T(r+1) = 10Cr (x<sup>2</sup>)<sup>10-r</sup> (x<sup>-3</sup>)<sup>r</sup> = 10Cr x<sup>20-2r-3r</sup> = 10Cr x<sup>20-5r</sup>. For independent term: 20-5r=0, r=4. T<sub>5</sub> = 10C4 = 210.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →