Zaymiey

📐 Mathematics  ·  Binomial Theorem  ·  JEE

Find the numerically greatest term in (2 - 3x)¹⁰ when x = 1.

Answer: T₇.

  • A T₅
  • B T₆
  • C T₇
  • D T₈

Correct answer: C. T₇

Explanation: |T(r+1)/Tr| = |(10-r+1)/r x (-3x/2)| = (11-r)/r x 3/2. Set >= 1: 3(11-r) >= 2r. 33-3r >= 2r. 33 >= 5r. r <= 6.6. Check r=6: T<sub>7</sub>/T<sub>6</sub> = 5/6 x 3/2 = 15/12 > 1, so T<sub>7</sub> > T<sub>6</sub>. Check r=7: T<sub>8</sub>/T<sub>7</sub> = 4/7 x 3/2 = 12/14 < 1, so T<sub>8</sub> < T<sub>7</sub>. So T<sub>7</sub> is the greatest term.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →