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📐 Mathematics  ·  Binomial Theorem  ·  JEE

Find the coefficient of x² in (x + 2)⁵.

Answer: 80.

  • A 40
  • B 160
  • C 80
  • D 10

Correct answer: C. 80

Explanation: T(r+1) = 5Cr x<sup>5-r</sup> 2<sup>r.</sup> For x<sup>2</sup>: 5-r=2, r=3. T<sub>4</sub> = 5C3 x<sup>2</sup> x 2<sup>3</sup> = 10 x 8 x x<sup>2</sup> = 80x<sup>2.</sup> Coefficient = 80.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

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