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📐 Mathematics  ·  Application of Derivatives  ·  JEE

A spherical balloon's volume increases at 100 cm³/s. When the radius is 5 cm, the radius increases at:

Answer: 1/π cm/s.

  • A 1/π cm/s
  • B 1/(2π) cm/s
  • C 1/(4π) cm/s
  • D π cm/s

Correct answer: A. 1/π cm/s

Explanation: dV/dt = 4πr²·dr/dt gives dr/dt = 100/(4π·25) = 1/π cm/s.

Tangent and Normal at a Point on a Curve(a,b)tangent (slope=f'(a))normal (slope=-1/f'(a))Tangent and normal are always perpendicular to each other at the point of contact

The tangent at a point touches the curve with slope f'(a); the normal is the line perpendicular to the tangent at that same point, with slope -1/f'(a) - together they describe the curve's local direction and the line "straight into" the curve.

Concept context

Use derivatives to study rate of change, increasing and decreasing functions, tangents and normals, and maxima and minima, with classic optimization problems.

Read the full Application of Derivatives notes →