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📐 Mathematics  ·  Application of Derivatives  ·  JEE

A man of height 2 m walks away from a lamp post of height 6 m at a speed of 1.5 m/s. Find the rate at which the length of his shadow increases.

Answer: 0.75 m/s.

  • A 0.5 m/s
  • B 0.75 m/s
  • C 1 m/s
  • D 1.5 m/s

Correct answer: B. 0.75 m/s

Explanation: Using similar triangles with distance x from pole and shadow length s: 6/(x+s) = 2/s gives 6s = 2x+2s, so 4s=2x, s=x/2. ds/dt = (1/2)(dx/dt) = (1/2)(1.5) = 0.75 m/s.

Tangent and Normal at a Point on a Curve(a,b)tangent (slope=f'(a))normal (slope=-1/f'(a))Tangent and normal are always perpendicular to each other at the point of contact

The tangent at a point touches the curve with slope f'(a); the normal is the line perpendicular to the tangent at that same point, with slope -1/f'(a) - together they describe the curve's local direction and the line "straight into" the curve.

Concept context

Use derivatives to study rate of change, increasing and decreasing functions, tangents and normals, and maxima and minima, with classic optimization problems.

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