Zaymiey

🧪 Chemistry  ·  Solutions  ·  NEET & JEE

Why is the observed value of the van 't Hoff factor (i) less than 1 for a solute like acetic acid in benzene?

Answer: Acetic acid molecules associate (dimerise) in benzene, reducing the effective number of particles in solution.

  • A Acetic acid molecules associate (dimerise) in benzene, reducing the effective number of particles in solution
  • B Benzene reacts chemically with acetic acid to form a new, more concentrated solute under normal conditions
  • C The molar mass of acetic acid effectively rises when dissolved in benzene due to solvation as generally observed
  • D Acetic acid dissociates into ions more readily when dissolved in benzene than in water in typical laboratory settings

Correct answer: A. Acetic acid molecules associate (dimerise) in benzene, reducing the effective number of particles in solution

Explanation: In a non-polar solvent like benzene, acetic acid molecules associate through hydrogen bonding to form dimers, decreasing the number of effective particles and giving i less than 1.

Vapour Pressure: Pure Solvent vs SolutionTVapour PPure solventSolution (lower VP)ΔTfTf(soln)Tf(pure)Dissolved solute lowers vapour pressure at every temperature, shifting Tf down and Tb up

Adding a non-volatile solute lowers the solvent's vapour pressure at every temperature, which is the root cause behind all four colligative properties: it shifts the freezing point down and the boiling point up.

Concept context

Learn how substances dissolve and form mixtures. Covers concentration terms, colligative properties (boiling point elevation, freezing point depression, osmotic pressure), and ideal vs non-ideal solution behaviour.

Read the full Solutions notes →