When NaCl is doped with 10 -3 mol% of SrCl 2 , the number of cation vacancies per mole of NaCl is (N A = 6.022 x 10 23 ):

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When NaCl is doped with 10^-3 mol% of SrCl₂, the number of cation vacancies per mole of NaCl is (N_A = 6.022 x 10²³):

Answer: 6.022 x 10¹⁸.

A 6.022 x 10¹⁶
B 6.022 x 10²⁰
C 6.022 x 10¹⁸
D 1.2 x 10¹⁹

Correct answer: C. 6.022 x 10¹⁸

Explanation: Each Sr²⁺ replaces two Na⁺ but occupies one site, creating one vacancy. 10^-3 mol% = 10^-5 mol, so vacancies = 10^-5 x N_A = 6.022 x 10¹⁸.

The three cubic unit cells: Simple Cubic has atoms only at corners; Body-Centred adds one atom at the centre; Face-Centred adds one atom at the centre of each of the 6 faces, giving the highest packing efficiency.

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Explore the ordered world of crystalline solids: unit cells, packing, defects, and how structure determines electrical and magnetic properties.

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When NaCl is doped with 10-3 mol% of SrCl2, the number of cation vacancies per mole of NaCl is (NA = 6.022 x 1023):

Concept context

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When NaCl is doped with 10^-3 mol% of SrCl₂, the number of cation vacancies per mole of NaCl is (N_A = 6.022 x 10²³):