When NaCl is doped with 10 -3 mol% of SrCl 2 , the number of cation vacancies per mole of NaCl is (N A = 6.022 x 10 23 ):

When NaCl is doped with 10 -3 mol% of…

Answer: 6.022 x 10 18.

A 6.022 x 1016
B 6.022 x 1020
C 6.022 x 1018
D 1.2 x 1019

Correct answer: C. 6.022 x 1018

Explanation: Each Sr2+ replaces two Na+ but occupies one site, creating one vacancy. 10-3 mol% = 10-5 mol, so vacancies = 10-5 x NA = 6.022 x 1018.

The three cubic unit cells: Simple Cubic has atoms only at corners; Body-Centred adds one atom at the centre; Face-Centred adds one atom at the centre of each of the 6 faces, giving the highest packing efficiency.

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Explore the ordered world of crystalline solids: unit cells, packing, defects, and how structure determines electrical and magnetic properties.

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When NaCl is doped with 10<sup>-3</sup> mol% of SrCl<sub>2</sub>, the number of cation vacancies per mole of NaCl is (N<sub>A</sub> = 6.022 x 10<sup>23</sup>):

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