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🧪 Chemistry  ·  Solid State  ·  NEET & JEE

In the non-stoichiometric oxide Fe<sub>0.93</sub>O, the percentage of iron present as Fe<sup>3+</sup> ions is approximately:

Answer: 15%.

  • A 7%
  • B 10%
  • C 15%
  • D 23%

Correct answer: C. 15%

Explanation: Charge balance: 2a + 3b = 2 with a + b = 0.93 gives b(Fe<sup>3+</sup>) = 0.14, so % Fe<sup>3+</sup> = 0.14/0.93 x 100 = 15%.

Cubic Unit Cells: Atom PositionsSimple CubicCN=6, 52.4% packedBody-Centred (BCC)CN=8, 68% packedFace-Centred (FCC)CN=12, 74% packed (densest)Corner atoms (shared by 8 cells) shown lighter; body/face-centre atoms shown solid

The three cubic unit cells: Simple Cubic has atoms only at corners; Body-Centred adds one atom at the centre; Face-Centred adds one atom at the centre of each of the 6 faces, giving the highest packing efficiency.

Concept context

Explore the ordered world of crystalline solids: unit cells, packing, defects, and how structure determines electrical and magnetic properties.

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